


1.
Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of Rajeev? [Hotel Management, 2002]
2.
The ages of two persons differ by 16 years. If 6 years ago, the elder one be 3 times as old as the younger one, find their present ages. [A.A.O. Exam, 2003]
3.
The product of the ages of Ankit and Nikita is 240. If twice the age of Nikita is more than Ankit's age by 4 years, what is Nikita's age? [S.B.I.P.O. 1999]
4.
The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. Find the presentage of the father. [S.S.C. 2003]
5.
Rohit was 4 times as old as his son 8 years ago. After 8 years, Rohit will be twice as old as his son. What are their present ages?
Answer & Solution
Answer: c) 16 years and 40 years
Solution: Let son's age 8 years ago be x years. Then, Rohit's age 8 years ago = 4x years Son's age after 8 years = (x + 8) + 8 = (x + 16) years Rohit's age after 8 years = (4x + 8) + 8 = (4x + 16) years 2 (x + 16) = 4x + 16 => 2x = 16 => x = 8 Hence, son's present age = (x + 8) = 16 years Rohit's present age = (4x + 8) = 40 years 6.
One year ago, the ratio of Gaurav's and Sachin's age was 6 : 7 respectively. Four years hence, this ratio would become 7 : 8. How old is Sachin? [NABARD, 2002]
Answer & Solution
Answer: b) 36 years
Solution: Let Gaurav's and Sachin's ages one year ago be 6x and 7x years respectively Then, Gaurav's age 4 years hence = (6x + 1) + 4 = (6x + 5) years Sachin's age 4 years hence = (7x + 1) + 4 = (7x + 1) + 4 = (7x + 5) years [(6x + 5)/(7x + 5)] = 7/8 => 8 (6x + 5) = 7 (7x + 5) => 48x + 40 = 49x + 35 => x = 5 Hence, Sachin's present age = (7x + 1) = 36 years 7.
Abhay's age after six years will be threeseventh of his father's age. Ten years ago, ratio of their ages was 1 : 5. What is Abhay's father's age at present ?
Answer & Solution
Answer: c) 50 years
Solution: Let the age of Abhay and his father 10 years ago be x and 5x respectively. Then, Abhay's age after 6 years = (x + 10) + 6 = (x + 16) years Father's age after 6 years = (5x + 10) + 6 = (5x + 16) years (x + 16) = 3/7(5x + 16) => 7 (x + 16) = 3 (5x + 16) => 7x + 112 = 15x + 48 => 8x = 64 => x = 8 Hence, Abhay's father's present age = (5x + 10) = 50 years 