


1.
What was the day of the week on 16th July, 1776 ?
Answer & Solution
Answer: (B) Tuesday
Solution: 16th July 1776 = (1775 years + Period from 1.1.1776 to 16.7.1776) Counting of odd days : Number of odd days in 1600 years = 0 Number of odd days in 100 years = 5 75 years = 18 leap years + 57 ordinary years = (18 * 2 + 57 * 1) odd days = 93 odd days = (13 weeks + 2 days) = 2 odd days 1775 years have = (0 + 5 + 2) odd days = 7 odd days = 0 odd days Jan. + Feb. + March + April + May + June + July (31 + 29 + 31 + 30 +31 + 30 +16) = 198 days 198 days = (28 weeks + 2 days) = 2 odd days Total number of odd days = (0 + 2) = 2 Hence, the required day is Tuesday 2.
What was the day of the week on 15th August 1947?
Answer & Solution
Answer: (C) Friday
Solution: 15th August 1947 = (1946 years + Period from 1.1.1947 to 15.8.1947) Counting of odd days: Odd days in 1600 years = 0 Odd days in 300 years = (5 * 3) = 15 = 1 46 years = (11 leap years + 35 ordinary years) = (11 * 2 + 35 * 1) odd days = 57 odd days = (8 weeks + 1 day) = 1 odd day Odd days in 1946 years = (0 + 1 + 1) = 2 days Jan. + Fab. + March + April + May + June + July + Aug. (31 + 28 + 31 + 30 + 31 + 30 + 31 + 15) = 227 days 227 days = (32 weeks + 3 days) = 3 odd days Total number of odd days = (2 + 3) = 5 Hence, the required day is Friday. 3.
What was the day of the week on 4th June, 2002?
Answer & Solution
Answer: (C) Tuesday
Solution: 4th June, 2002 = (2001 years + Period from 1.1.2002 to 4.6.2002) Counting of odd days: Odd days in 1600 years = 0 Odd days in 1 ordinary year = 1 Odd days in 2001 years = (0 + 0 + 1) = 1 Jan. + Feb. + March + April + May + June (31 + 28 + 31 + 30 + 31 + 4) = 155 days = 22 weeks + 1 day = 1 odd day Total number of odd days = (1 + 1) = 2 Required day is Tuesday. 4.
On what dates of March 2005 did Friday fall?
Answer & Solution
Answer: (D) 4th, 11th, 18th, 25th
Solution: First we find the day on 1.3.2005 1.3.2005 = (2004 years + Period from 1.1.2005 to 1.3.2005 Odd days in 1600 years = 0 Odd days in 400 years = 0 4 years = ( 1 leap year + 3 ordinary years) = (1 * 2 + 3 * 1) odd days = 5 odd days Jan. + Feb. + March (31 + 28 + 1) = 60 days = (8 weeks + 4 days) = 4 odd days. Total number of odd days = (0 + 0 + 5 + 4) = 9 = 2 odd day 1.3.2005 was Tuesday. So, Friday lies on 4.3.2005 Hence, Friday lies on 4th, 11th, 18th, 25th of March, 2005. 5.
Prove that the Calendar for the year 2003 will serve for the year 2014.
Answer & Solution
Answer: (B) True
Solution: We must have same day on 1.1.2003 and 1.1.2014 So, number of odd days between 31.12.2002 and 31.12.2013 must be 0. This period has 3 leap years and 8 ordinary years. Number of odd days = (3 * 2 + 8 * 1) = 14 ≡ 0 odd day. Calendar for the year2003 will serve for the year 2014 6.
January 1, 2007 was Monday. What day of the week lies on January, 2008?
7.
January1, 2008 is Tuesday. What day of the week lies on January 1, 2009 ?
