# Time and Distance - Aptitude Questions and Answers - RejinpaulPlacement

29.
The speed of a car increases by 2 kms after every one hour. If the distance travelled in the first hour was 35 kms, what was the total distance travelled in 12 hours? [Bank P.O 2003]

Solution:   Total distance travelled in 12 hours = (35 + 37 + 39 + upto 12 terms).

This is an A.P with first term, a = 35
Number of terms, n = 12,
Common difference d = 2.

Required distance = 12/2 [2 * 35 + (12 - 1) * 2]
= 6 (70 + 22) = 552 km.
30.
A train covers a distance of 10 km in 12 minutes. If its speed is decreased by 5 km/hr, the time taken by it to cover the same distance will be: [S.S.C. 1999]
Answer: d) 13 min 20 sec

Solution:   Speed = [10 * (60/12)] km/hr = 50 km/hr.
New speed = (50 - 5) km/hr = 45 km/hr.

Time taken = (10/45) hr
= [(2/9) * 60] min = 13 1/3 min = 13 min 20 sec.
31.
Anna left for city A from city B at 5.20 a.m. She travelled at the speed of 80 km/hr for 2 hours 15 minutes. After that the speed was reduced to 60 km/hr. If the distance between two cities is 350 kms, at what time did Anna reach city A? [Bank P.O. 1999]

Solution:   Distance covered in 2 hours 15 minutes i.e., 2   1/4 hrs = [80 * 9/4)] hrs = 180 hrs.

Time taken to cover remaining distance = [(350 - 180) / 60] hrs = 17/6 hrs.
= 2 5/6 hrs = 2 hrs 50 min.

Total time taken = (2 hrs 15 min + 2 hrs 50 min) = 5 hrs 5 min.

So, Anna reached city A at 10.25 a.m.
32.
An aeroplane covers a certain distance at a speed of 240 kmph in 5 hrs. To cover the same distance in 1   2/3 hours, it must travel at a speed of : [S.S.C 2000]

Solution:   Distance = (240 * 5) km = 1200 km.
Required speed = [1200 * (3/5)] km/hr = 720 km/hr.
33.
A salesman travels a distance of 50 km in 2 hours and 30 minutes. How much faster, in kilometers per hour, on an average, must he travel to make such a trip in 5/6 hour less time? [ Hotel Management 2002]

Solution:   Time required = (2 hrs 30 min - 50 min) = 1 hr 40 min = 1   2/3 hrs
Required Speed = [50 * (3/5)] km/hr = 30 km/hr.
Original speed = [50 * (2/5)] km/hr = 20 km/hr
Difference in speed = (30 - 20) km/hr = 10 km/hr.
34.
A person has to cover a distance of 6 km in 45 minutes. If he covers one-half of the distance in two-thirds of the total time, to cover the remaining distance in the remaining time, his speed (in km/hr) must be : [S.S.C 1999]

Solution:   Remaining distance = 3 km
Remaining time = [(1/3) * 45] min = 15 min = 1/4 hour.

Required Speed =(3 * 4) km/hr = 12 km/hr.
35.
A man performs 3/5 of the total journey by rail, 17/20 by bus and the remaining 6.5 km on foot. His total journey is :